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6.0
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@@ -3,3 +3,5 @@
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bank.dat
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.vscode/launch.json
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.vscode/tasks.json
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a.out
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bank_system
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@@ -0,0 +1,53 @@
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# BankManager — C 语言银行账户管理系统
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## 构建 & 运行
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```sh
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gcc bank.c account.c transaction.c file_io.c utils.c log.c graph.c hash.c -o bank_system
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./bank_system
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```
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`bank.h` 是唯一头文件,所有 `.c` 编译顺序无要求。
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## 项目布局
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所有源文件在根目录,无 `src/` 子目录。无包管理器、无构建系统、无测试框架。
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| 文件 | 职责 |
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|------|------|
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| `bank.c` | 主循环、菜单、权限路由 |
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| `account.c` | 开户、销户、登录、修改密码、查询全部账户 |
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| `transaction.c` | 存款、取款、查余额、转账 |
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| `file_io.c` | 二进制文件读写 (bank.dat) |
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| `utils.c` | 输入校验工具(`GetInputInt`/`GetInputDouble` 已定义但未被使用) |
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| `log.c` | 环形队列日志,支持 KMP 关键词搜索 |
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| `graph.c` | 从转账日志建邻接矩阵,分析客户间资金来往关系 |
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| `hash.c` | 哈希表,映射账户ID到数组下标,线性探测+墓碑标记 |
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| `bank.h` | 唯一头文件,声明所有公有函数和类型 |
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## 重要数据/约束
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- **Max 50 账户** (`MAX_ACCOUNTS`),全局数组 `g_astAccounts`,不使用 `malloc`。
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- **`g_iAccCount` 初始值=1**(非0),槽位 0 预留给管理员。
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- **默认管理员**: ID=1000, name="admin", password=123456, quanxian=1。首次运行时自动创建。
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- **密码**: 纯 6 位数字(100000-999999)。
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- **权限**: 1=管理员,2=普通用户。
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- **数据持久化**: 二进制文件 `bank.dat`(已加入 `.gitignore`)。`SaveData()` 总是写入恰好 50 条记录。
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- **全局日志队列**: 环形队列 `g_logQueue`,最多 100 条 (`MAX_LOGS`),溢出时队头出队覆盖旧记录。
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- **哈希表**: `HASH_SIZE=101`(质数),开放寻址法+线性探测,删除用墓碑标记(id=-2)。
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## 代码约定
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- 中文注释和中文菜单字符串。
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- 全局变量命名前缀 `g_`(如 `g_iAccCount`, `g_astAccounts`)。
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- 无测试。
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## 已知陷阱
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- **`InitAdminAccount()` 双重调用导致密码重置** — `LoadData()` 内无文件时调用一次,`main()` 第 21 行无条件再调用一次。管理员密码修改在重启后必然丢失。
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- **`SaveData()` 内部调用 `LoadData()`**(`file_io.c:22`),写盘后立即重读以重新计数 `g_iAccCount`。注意这会导致刚保存的数组被覆盖读回。
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- **`GenerateDummyData()`(graph.c)会清空全部日志并修改账户余额**,仅用于测试演示,非生产操作。
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- **`DeleteAccount()` 不递减 `g_iAccCount`** — 递减由调用方 `bank.c:84` 负责。函数内 `for (; i < g_iAccCount-i; i++)` 边界有误(应为 `g_iAccCount-1`)。
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- **`exit(0)` 短路** — `bank.c:53` 直接 `exit(0)`,不会执行 `main()` 末尾的清理代码(当前无实质性清理,但未来加逻辑时需注意)。
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- **`ChangePassword()` 已定义但未接入菜单**(`account.c:159`),无法从界面调用。
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- **`utils.c` 的 `GetInputInt`/`GetInputDouble` 已定义但未被任何调用方使用**,全部输入仍用裸 `scanf`。
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@@ -13,11 +13,13 @@
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- 存款
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- 取款
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- 查询余额
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- 转账(账户间资金转移)
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- **系统功能**
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- 用户登录验证
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- 权限分级(管理员/普通用户)
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- 数据持久化(自动保存到文件)
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- 交易流水查询(管理员)
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- 资金关系图分析(管理员):从转账日志建图,分析客户间资金来往关系
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- 自动初始化默认管理员账户
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## 系统架构
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@@ -38,6 +40,7 @@
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- 存款功能
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- 取款功能
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- 余额查询
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- 转账功能(账户间资金转移)
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4. **数据持久化 (file_io.c)**
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- 数据保存到文件(bank.dat)
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@@ -54,7 +57,20 @@
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- 函数声明
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7. **日志模块(log.c)**
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- 日志记录和存储(循环链表)
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- 日志记录和存储(环形队列)
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8. **资金关系图分析(graph.c)**
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- 从转账日志构建邻接矩阵
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- 显示全部转账关系图
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- 查看指定账户关联关系
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- 最活跃账户排名(度中心性)
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- BFS最短转账路径查找
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9. **哈希表模块(hash.c)**
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- 映射账户ID到数组下标,O(1)快速查找
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- 开放寻址法,线性探测解决冲突
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- 墓碑标记处理删除操作
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- 支持从数组重建哈希表
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### 数据结构
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```c
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@@ -71,7 +87,7 @@ typedef struct strAccount
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## 使用说明
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### 编译
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```bash
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gcc bank.c account.c transaction.c file_io.c utils.c -o bank_system
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gcc bank.c account.c transaction.c file_io.c utils.c log.c graph.c hash.c -o bank_system
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```
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### 运行
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@@ -89,6 +105,7 @@ gcc bank.c account.c transaction.c file_io.c utils.c -o bank_system
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- 选项1:存款
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- 选项2:取款
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- 选项3:查询余额
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- 选项4:转账
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- 选项0:退出账户
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3. **管理员界面**(登录后)
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@@ -99,6 +116,9 @@ gcc bank.c account.c transaction.c file_io.c utils.c -o bank_system
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- 选项5:删除账户
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- 选项6:创建管理员账户
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- 选项7:查看交易流水
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- 选项8:搜索交易日志
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- 选项9:转账
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- 选项10:资金关系图分析
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- 选项0:退出账户
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### 默认账户
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@@ -113,7 +133,7 @@ gcc bank.c account.c transaction.c file_io.c utils.c -o bank_system
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- **密码规则**: 6位数字(100000-999999)
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- **数据存储**: 二进制文件(bank.dat)
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- **输入验证**: 所有数值输入都包含错误处理
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- **内存管理**: 使用全局数组存储账户数据
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- **内存管理**: 使用全局数组存储账户数据,哈希表加速ID查找
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## 文件说明
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- `bank.c` - 主程序文件
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@@ -121,6 +141,9 @@ gcc bank.c account.c transaction.c file_io.c utils.c -o bank_system
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- `transaction.c` - 交易处理功能实现
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- `file_io.c` - 文件读写功能实现
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- `utils.c` - 工具函数实现
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- `log.c` - 日志记录和存储(环形队列)
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- `graph.c` - 资金关系图分析模块
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- `hash.c` - 哈希表模块,映射账户ID到数组下标
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- `bank.h` - 头文件,包含结构体定义和函数声明
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- `bank.dat` - 数据存储文件(运行时自动生成)
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@@ -133,7 +156,7 @@ gcc bank.c account.c transaction.c file_io.c utils.c -o bank_system
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## 扩展建议
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- ~~添加交易记录功能~~
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- 实现账户排序和搜索
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- ~~实现账户快速搜索~~(已通过哈希表实现)
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- 增加更多权限级别
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- 改进用户界面(如使用图形界面)
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- 添加数据加密功能
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@@ -62,6 +62,7 @@ void CreateAccount(int quanxian)
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g_astAccounts[g_iAccCount] = stNewAcc;
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//把记录账户数量的全局变量自增。加过之后自增,所以下标0占用,数量是1个
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HashInsert(stNewAcc.id, g_iAccCount);
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g_iAccCount++;
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printf("开户成功! 账户ID: %d\n", stNewAcc.id);
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@@ -133,12 +134,7 @@ int LoginAccount(int temp_id) {
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*/
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int FindAccount(int id)
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{
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for(int i = 0; i < g_iAccCount; i++)
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{
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if(g_astAccounts[i].id == id) return i;
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}
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return -1;
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return HashSearch(id);
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}
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//删除账户
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void DeleteAccount(int id) {
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@@ -151,6 +147,7 @@ void DeleteAccount(int id) {
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printf("正在删除一下账户...");
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printf("%-8d %-30s %-10.2f %-3d\n",
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g_astAccounts[i].id, g_astAccounts[i].name, g_astAccounts[i].balance,g_astAccounts[i].quanxian);
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HashDelete(id);
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for (; i < g_iAccCount-i; i++)
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{
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g_astAccounts[i]=g_astAccounts[i+1];
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@@ -19,6 +19,7 @@ int main(void)
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printf("=== 简易银行账户管理系统 ===\n");
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printf("欢迎使用! 系统已加载%d个账户\n", g_iAccCount);
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InitAdminAccount();//初始化管理员账号
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RebuildHashTable();
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InitLogQueue();
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int iChoice=-1; //选择标志
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int pChoice=-1;
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@@ -59,7 +60,7 @@ int main(void)
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}
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break;
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case 1:
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printf("1. 存款\n2. 取款\n3. 查询\n4. 显示所有账户\n5. 删除账户\n6. 创建管理员账户\n7.查看交易\n日志0. 退出账户");
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printf("1. 存款\n2. 取款\n3. 查询\n4. 显示所有账户\n5. 删除账户\n6. 创建管理员账户\n7.查看交易日志\n8.搜索交易日志\n9.转账\n10.资金关系图分析\n0. 退出账户");
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pChoice=-1;
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scanf("%d", &pChoice);
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@@ -81,6 +82,7 @@ int main(void)
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scanf("%d", &d_id);
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DeleteAccount(d_id);
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g_iAccCount--;
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RebuildHashTable();
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break;
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case 6:
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CreateAccount(1);
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@@ -88,6 +90,65 @@ int main(void)
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case 7:
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ShowTransactionLogs();
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break;
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case 8:
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printf("请输入搜索内容");
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{
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char pattern[50];
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scanf("%s", pattern);
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SearchLogs(pattern);
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}
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break;
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case 9:
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Transfer(user_id);
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break;
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case 10:
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{
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int g_choice;
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do {
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printf("\n=== 资金关系图分析 ===\n");
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printf("1. 显示全部转账关系图\n");
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printf("2. 查看指定账户关联关系\n");
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printf("3. 查看最活跃账户排名\n");
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printf("4. 查找转账路径\n");
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printf("5. 生成虚拟交易记录\n");
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printf("0. 返回\n");
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printf("请选择: ");
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scanf("%d", &g_choice);
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switch(g_choice) {
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case 1:
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ShowTransferGraph();
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break;
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case 2: {
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int search_id;
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printf("请输入账户ID: ");
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scanf("%d", &search_id);
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ShowAccountRelations(search_id);
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break;
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}
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case 3:
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ShowMostActiveNodes();
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break;
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case 4: {
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int from, to;
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printf("请输入起始账户ID: ");
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scanf("%d", &from);
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printf("请输入目标账户ID: ");
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scanf("%d", &to);
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FindTransferPaths(from, to);
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break;
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}
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case 5:
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GenerateDummyData();
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break;
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case 0:
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break;
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default:
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printf("无效选择!\n");
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break;
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}
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} while (g_choice != 0);
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}
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break;
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case 0://EXIT
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printf("谢谢使用!\n按任意键退出");
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getchar();
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@@ -101,7 +162,7 @@ int main(void)
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}
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break;
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case 2:
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printf("1. 存款\n2. 取款\n3. 查询\n0.退出账户");
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printf("1. 存款\n2. 取款\n3. 查询\n4.转账\n0.退出账户");
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pChoice=-1;
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scanf("%d", &pChoice);
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switch(pChoice) {
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@@ -114,6 +175,9 @@ int main(void)
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case 3:
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QueryBalance(user_id);
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break;
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case 4:
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Transfer(user_id);
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break;
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case 0://EXIT
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printf("谢谢使用!\n按任意键退出");
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getchar();
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@@ -3,6 +3,7 @@
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#define MAX_LOGS 100 // 日志队列最大容量,防止无限增长
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#define MAX_ACCOUNTS 50 //系统规格为50个账户
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#define NAME_LEN 31 //用户名字最长30字符,因此需要多1个字符串结束符
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#define HASH_SIZE 101 //哈希表大小,取质数以减少冲突
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// 账户信息,每个账户id对应了名字、账户余额等信息,是不是用数据结构定义比较合适?
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typedef struct strAccount
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@@ -15,6 +16,21 @@ typedef struct strAccount
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} STACCOUNT;
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// strAccount STACCOUNT;
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// 哈希表条目,映射账户ID到g_astAccounts数组下标
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typedef struct {
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int id; // 账户ID,-1表示空槽位
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int index; // g_astAccounts中的下标
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} HashEntry;
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extern HashEntry g_hashTable[HASH_SIZE];
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// 哈希表操作
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void InitHashTable();
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int HashInsert(int id, int index);
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int HashSearch(int id);
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void HashDelete(int id);
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void RebuildHashTable();
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// 函数声明,main函数中调用的各模块函数需要在程序公用的.h中声明
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// 公开出来被其他模块调用的函数,也应该在公用的.h中声明
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@@ -54,7 +70,8 @@ void InitAdminAccount();
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// 日志条目结构
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typedef struct {
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int account_id; // 涉及的账户ID
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char type[10]; // 操作类型: "Deposit" 或 "Withdraw"
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int target_id; // 转账目标账户ID,非转账为-1
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char type[10]; // 操作类型: "Deposit","Withdraw","Transfer","Receive"
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double amount; // 交易金额
|
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double balance; // 交易后的余额
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char timestamp[20]; // 时间戳 (格式: YYYY-MM-DD HH:MM:SS)
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@@ -75,6 +92,19 @@ extern LogQueue g_logQueue;
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void InitLogQueue(); // 初始化队列
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int IsLogQueueFull(); // 检查队列是否满
|
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int IsLogQueueEmpty(); // 检查队列是否空
|
||||
int EnqueueLog(int id, const char* type, double amt, double bal); // 入队
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int EnqueueLog(int id, const char* type, double amt, double bal, int target); // 入队
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void ShowTransactionLogs(); // 显示所有日志
|
||||
|
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void SearchLogs(const char* pattern);//日志搜索
|
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|
||||
// 转账功能
|
||||
void Transfer(int from_id);
|
||||
|
||||
// 资金关系图分析
|
||||
void ShowTransferGraph();
|
||||
void ShowAccountRelations(int id);
|
||||
void ShowMostActiveNodes();
|
||||
void FindTransferPaths(int from_id, int to_id);
|
||||
void GenerateDummyData();
|
||||
|
||||
#endif
|
||||
|
||||
@@ -1,9 +1,6 @@
|
||||
#include <stdio.h>
|
||||
#include <stdlib.h>
|
||||
#include "bank.h"
|
||||
#include <io.h>
|
||||
|
||||
#define FILE_NAME bank.bat
|
||||
|
||||
//要操作的全局变量,但不在本模块定义需要声明为外部引入
|
||||
extern STACCOUNT g_astAccounts[];
|
||||
|
||||
@@ -0,0 +1,354 @@
|
||||
#include <stdio.h>
|
||||
#include <string.h>
|
||||
#include "bank.h"
|
||||
|
||||
extern LogQueue g_logQueue;
|
||||
extern STACCOUNT g_astAccounts[];
|
||||
extern int g_iAccCount;
|
||||
|
||||
// 从转账日志构建邻接矩阵,matrix[i][j] = 账户i向账户j的累计转账金额
|
||||
static void BuildAdjMatrix(int matrix[MAX_ACCOUNTS][MAX_ACCOUNTS])
|
||||
{
|
||||
int i, j;
|
||||
for (i = 0; i < g_iAccCount; i++)
|
||||
for (j = 0; j < g_iAccCount; j++)
|
||||
matrix[i][j] = 0;
|
||||
|
||||
if (IsLogQueueEmpty()) return;
|
||||
|
||||
int idx = g_logQueue.front;
|
||||
while (idx != g_logQueue.rear) {
|
||||
LogEntry e = g_logQueue.logs[idx];
|
||||
if (strcmp(e.type, "Transfer") == 0 && e.target_id > 0) {
|
||||
int from_idx = FindAccount(e.account_id);
|
||||
int to_idx = FindAccount(e.target_id);
|
||||
if (from_idx != -1 && to_idx != -1) {
|
||||
matrix[from_idx][to_idx] += (int)e.amount;
|
||||
}
|
||||
}
|
||||
idx = (idx + 1) % MAX_LOGS;
|
||||
}
|
||||
}
|
||||
|
||||
// 显示全部转账关系图
|
||||
void ShowTransferGraph()
|
||||
{
|
||||
int matrix[MAX_ACCOUNTS][MAX_ACCOUNTS];
|
||||
BuildAdjMatrix(matrix);
|
||||
|
||||
printf("\n=== 客户资金关系图 ===\n");
|
||||
printf("(连线表示转账关系,数字为累计转账金额)\n\n");
|
||||
|
||||
int has_transfer = 0;
|
||||
int i, j;
|
||||
for (i = 0; i < g_iAccCount; i++) {
|
||||
for (j = 0; j < g_iAccCount; j++) {
|
||||
if (matrix[i][j] > 0) {
|
||||
has_transfer = 1;
|
||||
printf("%s(%d) --[%d元]--> %s(%d)\n",
|
||||
g_astAccounts[i].name, g_astAccounts[i].id,
|
||||
matrix[i][j],
|
||||
g_astAccounts[j].name, g_astAccounts[j].id);
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
if (!has_transfer) {
|
||||
printf("暂无转账记录,无法构建关系图。\n");
|
||||
}
|
||||
}
|
||||
|
||||
// 查看指定账户的关联关系
|
||||
void ShowAccountRelations(int id)
|
||||
{
|
||||
int idx = FindAccount(id);
|
||||
if (idx == -1) {
|
||||
printf("账户不存在!\n");
|
||||
return;
|
||||
}
|
||||
|
||||
int matrix[MAX_ACCOUNTS][MAX_ACCOUNTS];
|
||||
BuildAdjMatrix(matrix);
|
||||
|
||||
printf("\n=== 账户关系分析: %s(%d) ===\n",
|
||||
g_astAccounts[idx].name, g_astAccounts[idx].id);
|
||||
|
||||
int j;
|
||||
int out_count = 0;
|
||||
int out_total = 0;
|
||||
printf("\n[转出记录]\n");
|
||||
for (j = 0; j < g_iAccCount; j++) {
|
||||
if (matrix[idx][j] > 0) {
|
||||
printf(" -> %s(%d): %d元\n",
|
||||
g_astAccounts[j].name, g_astAccounts[j].id, matrix[idx][j]);
|
||||
out_total += matrix[idx][j];
|
||||
out_count++;
|
||||
}
|
||||
}
|
||||
if (out_count == 0) printf(" 无转出记录\n");
|
||||
else printf(" 共转出 %d 笔, 合计 %d 元\n", out_count, out_total);
|
||||
|
||||
int i;
|
||||
int in_count = 0;
|
||||
int in_total = 0;
|
||||
printf("\n[转入记录]\n");
|
||||
for (i = 0; i < g_iAccCount; i++) {
|
||||
if (matrix[i][idx] > 0) {
|
||||
printf(" <- %s(%d): %d元\n",
|
||||
g_astAccounts[i].name, g_astAccounts[i].id, matrix[i][idx]);
|
||||
in_total += matrix[i][idx];
|
||||
in_count++;
|
||||
}
|
||||
}
|
||||
if (in_count == 0) printf(" 无转入记录\n");
|
||||
else printf(" 共转入 %d 笔, 合计 %d 元\n", in_count, in_total);
|
||||
|
||||
printf("\n总结: 转出%d笔(共%d元), 转入%d笔(共%d元)\n",
|
||||
out_count, out_total, in_count, in_total);
|
||||
}
|
||||
|
||||
// 查看最活跃账户排名(按转账关系数量排序)
|
||||
void ShowMostActiveNodes()
|
||||
{
|
||||
int matrix[MAX_ACCOUNTS][MAX_ACCOUNTS];
|
||||
BuildAdjMatrix(matrix);
|
||||
|
||||
int degrees[MAX_ACCOUNTS];
|
||||
int account_ids[MAX_ACCOUNTS];
|
||||
int i, j;
|
||||
int count = 0;
|
||||
|
||||
for (i = 0; i < g_iAccCount; i++) {
|
||||
int deg = 0;
|
||||
for (j = 0; j < g_iAccCount; j++) {
|
||||
if (matrix[i][j] > 0) deg++;
|
||||
if (matrix[j][i] > 0) deg++;
|
||||
}
|
||||
if (deg > 0) {
|
||||
degrees[count] = deg;
|
||||
account_ids[count] = i;
|
||||
count++;
|
||||
}
|
||||
}
|
||||
|
||||
if (count == 0) {
|
||||
printf("\n暂无转账关系数据。\n");
|
||||
return;
|
||||
}
|
||||
|
||||
// 冒泡排序(最多50个元素)
|
||||
for (i = 0; i < count - 1; i++) {
|
||||
for (j = 0; j < count - 1 - i; j++) {
|
||||
if (degrees[j] < degrees[j + 1]) {
|
||||
int tmp_d = degrees[j];
|
||||
degrees[j] = degrees[j + 1];
|
||||
degrees[j + 1] = tmp_d;
|
||||
int tmp_id = account_ids[j];
|
||||
account_ids[j] = account_ids[j + 1];
|
||||
account_ids[j + 1] = tmp_id;
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
printf("\n=== 最活跃账户排名 ===\n");
|
||||
printf("%-4s %-8s %-20s %-10s\n", "排名", "ID", "姓名", "关系数");
|
||||
printf("-----------------------------------------\n");
|
||||
int top = count < 10 ? count : 10;
|
||||
for (i = 0; i < top; i++) {
|
||||
int idx = account_ids[i];
|
||||
printf("%-4d %-8d %-20s %-10d\n",
|
||||
i + 1, g_astAccounts[idx].id,
|
||||
g_astAccounts[idx].name, degrees[i]);
|
||||
}
|
||||
}
|
||||
|
||||
// 用BFS查找两个账户间的最短转账路径
|
||||
void FindTransferPaths(int from_id, int to_id)
|
||||
{
|
||||
int from_idx = FindAccount(from_id);
|
||||
int to_idx = FindAccount(to_id);
|
||||
|
||||
if (from_idx == -1) { printf("源账户不存在!\n"); return; }
|
||||
if (to_idx == -1) { printf("目标账户不存在!\n"); return; }
|
||||
if (from_id == to_id) { printf("同一账户无需查找路径。\n"); return; }
|
||||
|
||||
int matrix[MAX_ACCOUNTS][MAX_ACCOUNTS];
|
||||
BuildAdjMatrix(matrix);
|
||||
|
||||
// BFS
|
||||
int visited[MAX_ACCOUNTS] = {0};
|
||||
int parent[MAX_ACCOUNTS];
|
||||
int queue[MAX_ACCOUNTS];
|
||||
int q_front = 0, q_rear = 0;
|
||||
int i;
|
||||
|
||||
for (i = 0; i < MAX_ACCOUNTS; i++) parent[i] = -1;
|
||||
|
||||
queue[q_rear++] = from_idx;
|
||||
visited[from_idx] = 1;
|
||||
|
||||
int found = 0;
|
||||
while (q_front < q_rear) {
|
||||
int curr = queue[q_front++];
|
||||
if (curr == to_idx) { found = 1; break; }
|
||||
int j;
|
||||
for (j = 0; j < g_iAccCount; j++) {
|
||||
if (matrix[curr][j] > 0 && !visited[j]) {
|
||||
visited[j] = 1;
|
||||
parent[j] = curr;
|
||||
queue[q_rear++] = j;
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
if (!found) {
|
||||
printf("未找到从 %d 到 %d 的转账路径。\n", from_id, to_id);
|
||||
return;
|
||||
}
|
||||
|
||||
// 回溯路径
|
||||
int path[MAX_ACCOUNTS];
|
||||
int path_len = 0;
|
||||
int curr = to_idx;
|
||||
while (curr != -1) {
|
||||
path[path_len++] = curr;
|
||||
curr = parent[curr];
|
||||
}
|
||||
|
||||
printf("\n=== 转账路径: %s(%d) -> %s(%d) ===\n",
|
||||
g_astAccounts[from_idx].name, from_id,
|
||||
g_astAccounts[to_idx].name, to_id);
|
||||
printf("最短路径长度: %d 步\n", path_len - 1);
|
||||
|
||||
for (i = path_len - 1; i >= 0; i--) {
|
||||
printf("%s(%d)", g_astAccounts[path[i]].name, g_astAccounts[path[i]].id);
|
||||
if (i > 0) {
|
||||
printf(" --[%d元]--> ", matrix[path[i]][path[i - 1]]);
|
||||
}
|
||||
}
|
||||
printf("\n");
|
||||
}
|
||||
|
||||
// 生成虚拟交易记录,用于测试资金关系图分析
|
||||
void GenerateDummyData()
|
||||
{
|
||||
int i;
|
||||
int orig_count = g_iAccCount;
|
||||
|
||||
// 如果账户不足5个,先创建测试账户(密码统一123456)
|
||||
if (g_iAccCount < 5 && g_iAccCount < MAX_ACCOUNTS) {
|
||||
int target = 5;
|
||||
if (target > MAX_ACCOUNTS) target = MAX_ACCOUNTS;
|
||||
|
||||
for (i = g_iAccCount; i < target; i++) {
|
||||
g_astAccounts[i].id = 1000 + i;
|
||||
g_astAccounts[i].balance = (i + 1) * 5000.0;
|
||||
g_astAccounts[i].password = 123456;
|
||||
g_astAccounts[i].quanxian = 2;
|
||||
g_astAccounts[i].name[0] = '\0';
|
||||
}
|
||||
|
||||
// 给账户起中文名
|
||||
if (orig_count <= 1) strcpy(g_astAccounts[1].name, "张三");
|
||||
if (orig_count <= 2) strcpy(g_astAccounts[2].name, "李四");
|
||||
if (orig_count <= 3) strcpy(g_astAccounts[3].name, "王五");
|
||||
if (orig_count <= 4) strcpy(g_astAccounts[4].name, "赵六");
|
||||
|
||||
g_iAccCount = target;
|
||||
SaveData();
|
||||
printf("已补充创建%d个测试账户\n", target - orig_count);
|
||||
}
|
||||
|
||||
// 如果有第6个槽位,创建一个钱七
|
||||
if (g_iAccCount < 6 && g_iAccCount < MAX_ACCOUNTS) {
|
||||
i = g_iAccCount;
|
||||
g_astAccounts[i].id = 1000 + i;
|
||||
strcpy(g_astAccounts[i].name, "钱七");
|
||||
g_astAccounts[i].balance = 20000.0;
|
||||
g_astAccounts[i].password = 123456;
|
||||
g_astAccounts[i].quanxian = 2;
|
||||
g_iAccCount++;
|
||||
SaveData();
|
||||
printf("已创建测试账户: 钱七(1005)\n");
|
||||
}
|
||||
|
||||
// 清空旧日志,生成新的虚拟交易流水
|
||||
InitLogQueue();
|
||||
|
||||
int id[6];
|
||||
for (i = 0; i < g_iAccCount && i < 6; i++)
|
||||
id[i] = g_astAccounts[i].id;
|
||||
|
||||
// 为每个账户存入初始资金(留痕)
|
||||
for (i = 1; i < g_iAccCount && i < 6; i++) {
|
||||
double bal = g_astAccounts[i].balance;
|
||||
EnqueueLog(id[i], "Deposit", bal, bal, -1);
|
||||
}
|
||||
|
||||
// 构建一个互联的转账网络:
|
||||
// 张三 -> 李四 3000
|
||||
// 李四 -> 王五 2000
|
||||
// 王五 -> 赵六 1500
|
||||
// 赵六 -> 钱七 1000
|
||||
// 钱七 -> 张三 800 (形成闭环,可测路径查找)
|
||||
// 张三 -> 王五 1200 (增加多条边)
|
||||
// 李四 -> 钱七 600
|
||||
|
||||
if (g_iAccCount >= 2) {
|
||||
// 张三(1) -> 李四(2): 3000
|
||||
g_astAccounts[1].balance -= 3000;
|
||||
g_astAccounts[2].balance += 3000;
|
||||
EnqueueLog(id[1], "Transfer", 3000, g_astAccounts[1].balance, id[2]);
|
||||
EnqueueLog(id[2], "Receive", 3000, g_astAccounts[2].balance, id[1]);
|
||||
}
|
||||
if (g_iAccCount >= 3) {
|
||||
// 李四(2) -> 王五(3): 2000
|
||||
g_astAccounts[2].balance -= 2000;
|
||||
g_astAccounts[3].balance += 2000;
|
||||
EnqueueLog(id[2], "Transfer", 2000, g_astAccounts[2].balance, id[3]);
|
||||
EnqueueLog(id[3], "Receive", 2000, g_astAccounts[3].balance, id[2]);
|
||||
// 张三(1) -> 王五(3): 1200
|
||||
g_astAccounts[1].balance -= 1200;
|
||||
g_astAccounts[3].balance += 1200;
|
||||
EnqueueLog(id[1], "Transfer", 1200, g_astAccounts[1].balance, id[3]);
|
||||
EnqueueLog(id[3], "Receive", 1200, g_astAccounts[3].balance, id[1]);
|
||||
}
|
||||
if (g_iAccCount >= 4) {
|
||||
// 王五(3) -> 赵六(4): 1500
|
||||
g_astAccounts[3].balance -= 1500;
|
||||
g_astAccounts[4].balance += 1500;
|
||||
EnqueueLog(id[3], "Transfer", 1500, g_astAccounts[3].balance, id[4]);
|
||||
EnqueueLog(id[4], "Receive", 1500, g_astAccounts[4].balance, id[3]);
|
||||
}
|
||||
if (g_iAccCount >= 5) {
|
||||
// 赵六(4) -> 钱七(5): 1000
|
||||
g_astAccounts[4].balance -= 1000;
|
||||
g_astAccounts[5].balance += 1000;
|
||||
EnqueueLog(id[4], "Transfer", 1000, g_astAccounts[4].balance, id[5]);
|
||||
EnqueueLog(id[5], "Receive", 1000, g_astAccounts[5].balance, id[4]);
|
||||
// 钱七(5) -> 张三(1): 800 (闭环)
|
||||
g_astAccounts[5].balance -= 800;
|
||||
g_astAccounts[1].balance += 800;
|
||||
EnqueueLog(id[5], "Transfer", 800, g_astAccounts[5].balance, id[1]);
|
||||
EnqueueLog(id[1], "Receive", 800, g_astAccounts[1].balance, id[5]);
|
||||
// 李四(2) -> 钱七(5): 600
|
||||
g_astAccounts[2].balance -= 600;
|
||||
g_astAccounts[5].balance += 600;
|
||||
EnqueueLog(id[2], "Transfer", 600, g_astAccounts[2].balance, id[5]);
|
||||
EnqueueLog(id[5], "Receive", 600, g_astAccounts[5].balance, id[2]);
|
||||
}
|
||||
|
||||
// 为部分账户生成取款记录
|
||||
if (g_iAccCount >= 3) {
|
||||
g_astAccounts[1].balance -= 500;
|
||||
EnqueueLog(id[1], "Withdraw", 500, g_astAccounts[1].balance, -1);
|
||||
g_astAccounts[3].balance -= 300;
|
||||
EnqueueLog(id[3], "Withdraw", 300, g_astAccounts[3].balance, -1);
|
||||
}
|
||||
|
||||
SaveData();
|
||||
printf("已生成 %d 条虚拟交易记录\n",
|
||||
(g_logQueue.rear - g_logQueue.front + MAX_LOGS) % MAX_LOGS);
|
||||
printf("账户数量: %d\n", g_iAccCount);
|
||||
printf("转账网络已构建: 张三->李四->王五->赵六->钱七->张三(闭环)\n");
|
||||
}
|
||||
@@ -0,0 +1,91 @@
|
||||
#include <stdio.h>
|
||||
#include "bank.h"
|
||||
|
||||
extern STACCOUNT g_astAccounts[];
|
||||
extern int g_iAccCount;
|
||||
|
||||
HashEntry g_hashTable[HASH_SIZE];
|
||||
|
||||
static int HashFunc(int id)
|
||||
{
|
||||
return id % HASH_SIZE;
|
||||
}
|
||||
|
||||
void InitHashTable()
|
||||
{
|
||||
int i;
|
||||
for (i = 0; i < HASH_SIZE; i++) {
|
||||
g_hashTable[i].id = -1;
|
||||
g_hashTable[i].index = -1;
|
||||
}
|
||||
}
|
||||
|
||||
int HashInsert(int id, int index)
|
||||
{
|
||||
int pos = HashFunc(id);
|
||||
int first_tombstone = -1;
|
||||
int i;
|
||||
for (i = 0; i < HASH_SIZE; i++) {
|
||||
int probe = (pos + i) % HASH_SIZE;
|
||||
if (g_hashTable[probe].id == id) {
|
||||
g_hashTable[probe].index = index;
|
||||
return 0;
|
||||
}
|
||||
if (g_hashTable[probe].id == -1) {
|
||||
if (first_tombstone != -1) {
|
||||
probe = first_tombstone;
|
||||
}
|
||||
g_hashTable[probe].id = id;
|
||||
g_hashTable[probe].index = index;
|
||||
return 0;
|
||||
}
|
||||
if (g_hashTable[probe].id == -2 && first_tombstone == -1) {
|
||||
first_tombstone = probe;
|
||||
}
|
||||
}
|
||||
return -1;
|
||||
}
|
||||
|
||||
int HashSearch(int id)
|
||||
{
|
||||
int pos = HashFunc(id);
|
||||
int i;
|
||||
for (i = 0; i < HASH_SIZE; i++) {
|
||||
int probe = (pos + i) % HASH_SIZE;
|
||||
if (g_hashTable[probe].id == id) {
|
||||
return g_hashTable[probe].index;
|
||||
}
|
||||
if (g_hashTable[probe].id == -1) {
|
||||
return -1;
|
||||
}
|
||||
}
|
||||
return -1;
|
||||
}
|
||||
|
||||
void HashDelete(int id)
|
||||
{
|
||||
int pos = HashFunc(id);
|
||||
int i;
|
||||
for (i = 0; i < HASH_SIZE; i++) {
|
||||
int probe = (pos + i) % HASH_SIZE;
|
||||
if (g_hashTable[probe].id == -1) {
|
||||
return;
|
||||
}
|
||||
if (g_hashTable[probe].id == id) {
|
||||
g_hashTable[probe].id = -2;
|
||||
g_hashTable[probe].index = -1;
|
||||
return;
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
void RebuildHashTable()
|
||||
{
|
||||
int i;
|
||||
InitHashTable();
|
||||
for (i = 0; i < g_iAccCount; i++) {
|
||||
if (g_astAccounts[i].id != 0) {
|
||||
HashInsert(g_astAccounts[i].id, i);
|
||||
}
|
||||
}
|
||||
}
|
||||
@@ -31,7 +31,7 @@ void GetCurrentTimeStr(char* buf) {
|
||||
|
||||
// 入队操作:记录交易
|
||||
// 参数: 账户ID, 类型("Deposit"/"Withdraw"), 交易金额, 交易后余额
|
||||
int EnqueueLog(int id, const char* type, double amt, double bal) {
|
||||
int EnqueueLog(int id, const char* type, double amt, double bal, int target) {
|
||||
// 如果队列满,通过移动 front 指针覆盖最旧的日志 (环形队列特性)
|
||||
if (IsLogQueueFull()) {
|
||||
// 覆盖旧数据,队头自动出队
|
||||
@@ -44,6 +44,7 @@ int EnqueueLog(int id, const char* type, double amt, double bal) {
|
||||
strcpy(g_logQueue.logs[pos].type, type);
|
||||
g_logQueue.logs[pos].amount = amt;
|
||||
g_logQueue.logs[pos].balance = bal;
|
||||
g_logQueue.logs[pos].target_id = target;
|
||||
GetCurrentTimeStr(g_logQueue.logs[pos].timestamp);
|
||||
strcpy(g_logQueue.logs[pos].location, "宇宙总行"); // 根据你的需求固定地点
|
||||
|
||||
@@ -61,14 +62,122 @@ void ShowTransactionLogs() {
|
||||
}
|
||||
|
||||
printf("\n=== 交易流水日志 ===\n");
|
||||
printf("%-5s %-8s %-10s %-10s %-15s %-20s\n", "ID", "操作", "金额", "余额", "时间", "地点");
|
||||
printf("--------------------------------------------------------------\n");
|
||||
printf("%-5s %-8s %-10s %-10s %-10s %-15s %-20s\n", "ID", "操作", "金额", "余额", "目标", "时间", "地点");
|
||||
printf("-----------------------------------------------------------------------\n");
|
||||
|
||||
int i = g_logQueue.front;
|
||||
while (i != g_logQueue.rear) {
|
||||
LogEntry e = g_logQueue.logs[i];
|
||||
printf("%-5d %-8s %-10.2f %-10.2f %-15s %-20s\n",
|
||||
e.account_id, e.type, e.amount, e.balance, e.timestamp, e.location);
|
||||
printf("%-5d %-8s %-10.2f %-10.2f ", e.account_id, e.type, e.amount, e.balance);
|
||||
if (e.target_id > 0)
|
||||
printf("%-10d ", e.target_id);
|
||||
else
|
||||
printf("%-10s ", "-");
|
||||
printf("%-15s %-20s\n", e.timestamp, e.location);
|
||||
i = (i + 1) % MAX_LOGS;
|
||||
}
|
||||
}
|
||||
|
||||
// 1. 构建部分匹配表 (Next Array)
|
||||
// 这是KMP算法的核心预处理步骤
|
||||
void ComputeLPSArray(const char* pattern, int M, int* lps) {
|
||||
int len = 0; // length of the previous longest prefix suffix
|
||||
lps[0] = 0; // lps[0] is always 0
|
||||
int i = 1;
|
||||
|
||||
while (i < M) {
|
||||
if (pattern[i] == pattern[len]) {
|
||||
len++;
|
||||
lps[i] = len;
|
||||
i++;
|
||||
} else {
|
||||
if (len != 0) {
|
||||
len = lps[len - 1];
|
||||
} else {
|
||||
lps[i] = 0;
|
||||
i++;
|
||||
}
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
// 2. KMP 搜索函数
|
||||
// 在文本 text 中查找模式 pattern,找到后调用回调函数处理匹配位置
|
||||
void KMPSearch(const char* pattern, const char* text, void (*callback)(int)) {
|
||||
int M = strlen(pattern);
|
||||
int N = strlen(text);
|
||||
|
||||
if (M == 0) return;
|
||||
|
||||
// 创建并计算LPS数组
|
||||
int* lps = (int*)malloc(M * sizeof(int));
|
||||
ComputeLPSArray(pattern, M, lps);
|
||||
|
||||
int i = 0; // index for text
|
||||
int j = 0; // index for pattern
|
||||
|
||||
while (i < N) {
|
||||
if (pattern[j] == text[i]) {
|
||||
j++;
|
||||
i++;
|
||||
}
|
||||
|
||||
if (j == M) {
|
||||
// 找到匹配,调用回调函数输出该行或处理
|
||||
callback(i - j);
|
||||
j = lps[j - 1];
|
||||
} else if (i < N && pattern[j] != text[i]) {
|
||||
if (j != 0) {
|
||||
j = lps[j - 1];
|
||||
} else {
|
||||
i++;
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
free(lps);
|
||||
}
|
||||
|
||||
// 3. 回调函数:用于打印匹配到的日志行号
|
||||
void PrintMatchLine(int pos) {
|
||||
// 这里简化处理,实际应用中需要根据换行符计算行号
|
||||
// 或者直接打印匹配位置附近的上下文
|
||||
printf("找到匹配 (位置: %d)\n", pos);
|
||||
}
|
||||
|
||||
// 4. 对外接口:搜索交易日志
|
||||
void SearchLogs(const char* pattern) {
|
||||
if (IsLogQueueEmpty()) {
|
||||
printf("暂无日志可供搜索。\n");
|
||||
return;
|
||||
}
|
||||
|
||||
printf("\n=== 搜索日志: '%s' ===\n", pattern);
|
||||
|
||||
// 简化版:遍历每一条日志进行匹配
|
||||
int i = g_logQueue.front;
|
||||
int lineNum = 1;
|
||||
|
||||
while (i != g_logQueue.rear) {
|
||||
LogEntry e = g_logQueue.logs[i];
|
||||
|
||||
// 将日志条目格式化为字符串(模拟一行文本)
|
||||
char logLine[256];
|
||||
sprintf(logLine, "ID:%d Type:%s Amount:%.2f Balance:%.2f Target:%d Time:%s",
|
||||
e.account_id, e.type, e.amount, e.balance, e.target_id, e.timestamp);
|
||||
|
||||
// 使用KMP检查这一行是否包含模式
|
||||
// 这里为了演示调用了标准 strstr,你可以将其替换为上面的 KMPSearch
|
||||
// 但考虑到单行文本较短,KMP优势不大;如果是超长日志文件,KMP优势巨大
|
||||
|
||||
if (strstr(logLine, pattern) != NULL) {
|
||||
printf("%-3d %-8d %-10s %-10.2f %-15s",
|
||||
lineNum, e.account_id, e.type, e.amount, e.timestamp);
|
||||
if (e.target_id > 0) printf(" -> %d", e.target_id);
|
||||
printf("\n");
|
||||
}
|
||||
|
||||
i = (i + 1) % MAX_LOGS;
|
||||
lineNum++;
|
||||
}
|
||||
}
|
||||
+57
-2
@@ -31,7 +31,7 @@ void Deposit(int id)
|
||||
g_astAccounts[FindAccount(id)].balance+=amount;
|
||||
printf("success");
|
||||
QueryBalance(id);
|
||||
EnqueueLog(id, "Deposit", amount, g_astAccounts[FindAccount(id)].balance);
|
||||
EnqueueLog(id, "Deposit", amount, g_astAccounts[FindAccount(id)].balance, -1);
|
||||
SaveData();
|
||||
break;
|
||||
}
|
||||
@@ -69,7 +69,7 @@ void Withdraw(int id)
|
||||
if (g_astAccounts[FindAccount(id)].password==temp_password) {
|
||||
if (g_astAccounts[FindAccount(id)].balance>amount) {
|
||||
g_astAccounts[FindAccount(id)].balance-=amount;
|
||||
EnqueueLog(id, "Withdraw", amount, g_astAccounts[FindAccount(id)].balance);
|
||||
EnqueueLog(id, "Withdraw", amount, g_astAccounts[FindAccount(id)].balance, -1);
|
||||
printf("success");
|
||||
QueryBalance(id);
|
||||
SaveData();
|
||||
@@ -100,3 +100,58 @@ void QueryBalance(int id)
|
||||
printf("你现在还有%f块\n",g_astAccounts[FindAccount(id)].balance);
|
||||
return;
|
||||
}
|
||||
|
||||
void Transfer(int from_id)
|
||||
{
|
||||
int to_id;
|
||||
int amount;
|
||||
int temp_password;
|
||||
int from_idx = FindAccount(from_id);
|
||||
int to_idx;
|
||||
|
||||
printf("请输入目标账户ID: ");
|
||||
scanf("%d", &to_id);
|
||||
|
||||
to_idx = FindAccount(to_id);
|
||||
if (to_idx == -1) {
|
||||
printf("目标账户不存在!\n");
|
||||
return;
|
||||
}
|
||||
if (from_id == to_id) {
|
||||
printf("不能给自己转账!\n");
|
||||
return;
|
||||
}
|
||||
|
||||
while (1) {
|
||||
printf("请输入转账金额: ");
|
||||
scanf("%d", &amount);
|
||||
if (amount > 0) break;
|
||||
printf("金额必须为正数!\n");
|
||||
}
|
||||
|
||||
printf("请输入密码验证身份: ");
|
||||
while (1) {
|
||||
scanf("%d", &temp_password);
|
||||
if (g_astAccounts[from_idx].password == temp_password) {
|
||||
if (g_astAccounts[from_idx].balance >= amount) {
|
||||
g_astAccounts[from_idx].balance -= amount;
|
||||
g_astAccounts[to_idx].balance += amount;
|
||||
EnqueueLog(from_id, "Transfer", amount,
|
||||
g_astAccounts[from_idx].balance, to_id);
|
||||
EnqueueLog(to_id, "Receive", amount,
|
||||
g_astAccounts[to_idx].balance, from_id);
|
||||
printf("转账成功! %d -> %d, 金额: %d\n",
|
||||
from_id, to_id, amount);
|
||||
printf("当前余额: %.2f\n", g_astAccounts[from_idx].balance);
|
||||
SaveData();
|
||||
return;
|
||||
} else {
|
||||
printf("余额不足! 当前余额: %.2f\n",
|
||||
g_astAccounts[from_idx].balance);
|
||||
return;
|
||||
}
|
||||
} else {
|
||||
printf("密码错误,请重新输入: ");
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
Reference in New Issue
Block a user